Basically, all load applied to the cantilever
Like to try your solution just to wind load I will get 16x3x5=240 cs Of CS will increase and we look only at wind load so far so if I would Please also noted that you assumed symmetrical load for both ends of theĬantilever when you try to create CS with unsymmetrical load the number Lifting frame position, let assume 5 (and 5 it is not much at all). Lifting frame position, but during erection, we will have more that one Just for wind load we will have 16 cs (2x*2y*4z) and this is for one The lifting frame with the current position of the lifting frame, andįirst of all the solution that you proposed theoretically couldĮven work (at least for wind load) however it is highly impractical, So only when we applied wind load atĬonstruction stage analysis we are able to easily correlate wind load on Load also to the Lifting frames, and the position of the lifting framesĭuring erection is changing. Then the best way is to add this load at construction stage analysis.īecause you need to remember that during erection we are applying wind But when we are looking at wind load during erection True but only partial because we can do that only for wind load at Wind load does not have been applied at construction stage analysis userĬan at that as superposition load after bridge erection and this is Vertical wind load should be used 4 cases). X- (and this is a very positive assumption since based on Eurocode for We are using 2 cases for each wind load direction: Z+, Z-, Y+, Y-, X+, We need at least 6 erection load cases for wind load, let's say When using spring supports it is usual to have to fix one bearing in the vertical direction to achieve a stable solution.Ī grillage does not analyse in-plane loading so any longitudinal or transverse restraint will not be modelled.4. The 'Fixed' bearing will be fixed or sprung in all directions.
Most grillage programs will allow the supports to be modelled as free, rigid or sprung.
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